#include <stdio.h>
#define SIZE 100
main()
{//initializig varibles

        int i,j,k,l,m,n,o,p,size;
        char number1[SIZE];
        char number2[SIZE];
	char multiply[SIZE*2];
	char sum[SIZE*2];        
	char symbol;
        char temp[SIZE];
        char carry1=0;
        char carry2=0;
	for(i=0;i<SIZE;i++)
	{	number1[i]=0;
		number2[i]=0;}
	for(l=0;l<SIZE*2;l++)				
	{	sum[l]=0;
		multiply[l]=0;		}
//input first number
        printf("Please enter the first number of atmost %d digits",SIZE);
	symbol=getchar();
	for(size=0;1;size++)
{	if(symbol<'0'||symbol>'9')
	{	printf("You must entre a digit of between 0 and 9");
		break;			}	
	if(size==SIZE)
	{printf("The number is too large");
	return;}
	temp[size]=symbol-48;
	symbol=getchar();	
}
//reversing the digits
	for(j=0;j<size;j++)
	number1[j]=temp[size-j-1];


//reading the second number


       printf("Please enter the second number of atmost %d digits",SIZE);
	symbol=getchar();
	for(size=0;1;size++)
{	if(symbol<'0'||symbol>'9')
	{	printf("You must entre a digit of between 0 and 9");
		break;			}	
	if(size==SIZE)
{	printf("The number is too large");
	return;}
	temp[size]=symbol-48;
	symbol=getchar();	
}
//reversing the digits
	for(j=0;j<size;j++)
	number2[j]=temp[size-j-1];

//multiplying the two numbers
	for(i=0;i<SIZE;i++)
{	
	for(j=0;j<SIZE;j++)
{	k=number2[j]*number1[i]+carry1;//performing multiplication with one digit
	multiply[i+j]=k%10;
	carry1=k/10;		}
	for(k=0;k<2*(SIZE);k++)
{
	m=multiply[k]+sum[k]+carry2;//performing addition
	sum[k]=m%10;
	carry2=m/10;     }
	for(i=0;i<2*SIZE;i++,multiply[i]=0);// making multiply[]=0
}
//printing the output

for (i = SIZE-1; i >= 0; i--)
		if (sum[i] > 0)
			break;
	
	if (i == 0) /* the sum is zero! */
		printf("The product is: 0\n");
	else {
		printf("The product is: ");
		for (; i >= 0; i--)
			putchar(sum[i]+'0');
		printf("\n");
	}

}