/*
 * To display the jobs that can be run on machines as a 4 X 3 matrix
 * @author-Karan Narain(karan@iitk.ac.in)
 *
*/

#include <stdio.h>
int main()
{
	int A[4][3],job,machine,i,j;
	//Initialize the matrix A to 0,indicating that initially no job can be run on any machine
	for(i=0;i<4;i++)
	{
		for(j=0;j<3;j++)
		{
			A[i][j]=0;
		}
	}

	for(i=0;i<8;i++)
	{
		printf("\nEnter job-machine pair number %d:\n",i+1);
		scanf("%d",&job);
		scanf("%d",&machine);
		//Check for invalid inputs,i.e.job>3 or machine>2
		if((job>3)||(machine>2))
		{
			printf("Invalid input.\n");
			//Decrement i and continue to repeat this iteration till a valid input is provided
			i=i-1;
			/*continue statement stops the current iteration and goes back to the for loop statement.Here i is incremented but since we had decremented i before continue,i gets the same value as before and the iteration is repeated*/ 
			continue;
		}
		//set 1 for the cell of the matrix that corresponds to this particular job and machine
		A[job][machine]=1;
	}
	printf("The job-machine matrix is as follows\n");
	for(i=0;i<4;i++)
	{
		for(j=0;j<3;j++)
		{
			printf("%d     ",A[i][j]);
		}
		printf("\n");
	}

}